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From: Boris Ostrovsky <boris.ostrovsky@oracle.com>
To: Juergen Gross <jgross@suse.com>,
xen-devel@lists.xenproject.org, linux-kernel@vger.kernel.org
Cc: Stefano Stabellini <sstabellini@kernel.org>,
Jan Beulich <jbeulich@suse.com>
Subject: Re: [PATCH] xen/balloon: use a kernel thread instead a workqueue
Date: Wed, 8 Sep 2021 10:47:16 -0400 [thread overview]
Message-ID: <8b13525b-0075-f4c1-8900-1be151e85e3e@oracle.com> (raw)
In-Reply-To: <20210827123206.15429-1-jgross@suse.com>
On 8/27/21 8:32 AM, Juergen Gross wrote:
> +static bool balloon_thread_cond(enum bp_state state, long credit)
> +{
> + if (state != BP_EAGAIN)
> + credit = 0;
> +
> + return current_credit() != credit || kthread_should_stop();
> +}
> +
> +/*
> + * As this is a kthread it is guaranteed to run as a single instance only.
> * We may of course race updates of the target counts (which are protected
> * by the balloon lock), or with changes to the Xen hard limit, but we will
> * recover from these in time.
> */
> -static void balloon_process(struct work_struct *work)
> +static int balloon_thread(void *unused)
> {
> enum bp_state state = BP_DONE;
> long credit;
> + unsigned long timeout;
> +
> + set_freezable();
> + for (;;) {
> + if (state == BP_EAGAIN)
> + timeout = balloon_stats.schedule_delay * HZ;
> + else
> + timeout = 3600 * HZ;
> + credit = current_credit();
>
> + wait_event_interruptible_timeout(balloon_thread_wq,
> + balloon_thread_cond(state, credit), timeout);
Given that wait_event_interruptible_timeout() is a bunch of nested macros do we need to worry here about overly aggressive compiler optimizing out 'credit = current_credit()'?
-boris
next prev parent reply other threads:[~2021-09-08 14:47 UTC|newest]
Thread overview: 4+ messages / expand[flat|nested] mbox.gz Atom feed top
2021-08-27 12:32 Juergen Gross
2021-09-08 14:47 ` Boris Ostrovsky [this message]
2021-09-08 15:11 ` Juergen Gross
2021-09-08 16:05 ` Boris Ostrovsky
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